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lim x—∞[ (x+1)/(x平方+1) ] arctanx
具体过程
人气:492 ℃ 时间:2020-03-18 06:14:40
解答
lim(x→+∞) [ (x+1)/(x²+1) ] arctanx
=lim(tan x→+∞) [ (tan x + 1)/(tan²x+1) ] arctan(tan x)
=lim(x→π/2) [sin x ·cos x + cos²x]·x
=lim(x→π/2) cos x(sin x + cos x)·x
=0·1·π/2
=0
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