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(a的n次方*b³)³ *a²*b的2n-7次方-(a的n+1次方*b)平方*(ab²)的n次方=
人气:110 ℃ 时间:2019-10-22 01:51:31
解答
原式=(a的n次方)³×(b³)³×a²×(b的2n-7次方)-[a的2(n+1)次方]×b²×(a的n次方)×(b的2n次方)
=(a的3n次方)×(b的9次方)×a²×(b的2n-7)次方-[a的2(n+1)+n次方]×(b的2n+2次方)
=(a的3n+2次方)×(b的9+2n-7次方)-(a的3n+2次方)×(b的2n+2次方)
=(a的3n+2次方)×(b的2n+2次方)-(a的3n+2次方)×(b的2n+2次方)
=0
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