1,sin[(-67/12)π]=sin[(-67/12)+6π]=sin(5/12π）=sin(π/4+π/6)=sin(π/4)cos(π/6)+ cos(π/4）sin(π/6)=(√6+√4）/42,tan(-15π/4)=tan(-15π/4+4π）=tan(π/4)=1,3,cos398°13‘=cos38°13’4.tan766°15...