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求下列各三角函数值:(1)sin(-1920°) (2)cos(-1560°) (3)tan(-17π/6)
人气:157 ℃ 时间:2020-04-02 01:45:21
解答
sin(-1920°)=sin(-1920°+360°*6)=sin(240°)=-√3/2
cos(-1560°)=cos(-1560°+360°*5)=cos(240°)=-1/2
tan(-17π/6)=tan(-17π/6+π*3)=tan(1/6π)=√3/3
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