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化简:cos(a-π/2)/sin(5π/2+a)*sin(a-2π)*cos(2π-a)
人气:474 ℃ 时间:2020-03-19 11:27:36
解答
是cos(a-π/2)/(sin(5π/2+a)*sin(a-2π)*cos(2π-a))么?
cos(a-π/2)=-sin(a); sin(5π/2+a)=sin(π/2+a)=cos(a); sin(a-2π)=sin(a); cos(2π-a)=cos(a)
剩下的就好算了
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