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当A=2-√3时,求代数式1-2A+A²/A-1-√A²-2A+1/A²-A-1/A的值
人气:403 ℃ 时间:2020-06-06 05:22:47
解答
a=1/(2+√3)=2-√3
1-2a+a²/a-1 -√a²-2a+1/a²-a
=(a-1)²/a-1 -√(a-1)²/[a(a-1)]
=(a-1)+(a-1)/[a(a-1)]
=a-1+1/a
=2-√3-1+(2+√3)
=3
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