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先化简,再求值(x-y+y^2/x+y)÷x^2,其中x、y满足|x-2y+1|+|2x-y-5|=0
如题
人气:462 ℃ 时间:2020-10-02 04:19:38
解答

根据绝对值为非负数得
x-2y+1=0
2x-y-5=0
联立解得
x=11/3 y=7/3
[x-y+y^2/(x+y)]÷x^2
=[(x-y)(x+y)+y^2]/(x+y)÷x^2
=(x²-y²+y²)/(x+y)÷x^2
=1/(x+y)
=1/(11/3+7/3)
=1/6
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