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稀释质量分数为98%的浓硫酸配置500ml质量分数为20%的稀硫酸
人气:266 ℃ 时间:2019-10-11 09:14:35
解答
设溶液的体积为V.(500mlx1.14g/ml)x20%=(Vx1.84g/ml)x98% 114g=1.84Vx0.98 1.84V=116.3ml V=63.2ml 所以须加入水的体积为500ml-63.2ml=436.8ml我来回答
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稀释质量分数为98%(密度为1.84g/ml)的浓硫酸配制500ml质量分数为20% 的稀硫酸(密度为1.14g/ml),稀释时需用水体积约为?
稀释质量分数为98%(密度为1.84g/mL)的浓硫酸配制500mL质量分数为20%的稀硫酸(密度为1.14g/mL),稀释时需用的水的体积约为( ) A.436.8mL B.453.7mL C.456.0mL D.458.3mL
稀释质量分数为98%(密度为1.84g/mL)的浓硫酸配制500mL质量分数为20%的稀硫酸(密度为1.14g/mL),稀释时需用的水的体积约为( ) A.436.8mL B.453.7mL C.456.0mL D.458.3mL
稀释质量分数为98%(密度为1.84g/mL)的浓硫酸配制500mL质量分数为20%的稀硫酸(密度为1.14g/mL),稀释时需用的水的体积约为( ) A.436.8mL B.453.7mL C.456.0mL D.458.3mL
悬赏分:10 稀释质量分数为98%(密度为1.84克每毫升)的浓硫酸配置500ml
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