abc |
ac+bc |
1 |
3 |
abc |
ab+ac |
1 |
4 |
abc |
bc+ab |
1 |
5 |
则ac+bc=3abc①,ab+ac=4abc②,bc+ab=5abc③,
①+②+③得,2(ab+bc+ca)=12abc,
即
abc |
ab+bc+ca |
2 |
12 |
1 |
6 |
故选A.
ab |
a+b |
1 |
3 |
bc |
b+c |
1 |
4 |
ca |
c+a |
1 |
5 |
abc |
ab+bc+ca |
1 |
6 |
1 |
12 |
2 |
15 |
1 |
20 |
abc |
ac+bc |
1 |
3 |
abc |
ab+ac |
1 |
4 |
abc |
bc+ab |
1 |
5 |
abc |
ab+bc+ca |
2 |
12 |
1 |
6 |