[1+cos(2ωx)]/2+[(√3)sin(2ωx)]/2,
原式=(1/2)+(1/2)cos(2ωx)+(√3/2)sin(2ωx)
=(1/2)+cos(2ωx)cos(π/3)+sin(2ωx)sin(π/3)
=cos(2ωx-π/3)+1/2.