3元2次a,t0,t10.1a=1-0.0008at03.6+0.5at平方/340=t0t0+0.2=t13.6+0.5at1的_数学解答

3元2次
a,t0,t1
0.1a=1-0.0008at0
3.6+0.5at平方/340=t0
t0+0.2=t1
3.6+0.5at1的平方/340=t0

人气：463 ℃　时间：2020-04-16 12:22:29

解答

为方便,记x=t0方程1化为：a=1/(0.1+0.0008x)将t1=t0+0.2及a代入方程2：3.6+0.5/(0.1+0.0008x)(x+0.2)²/340=x两边同是乘以340(0.1+0.0008x):1224(0.1+0.0008x)+0.5(x+0.2)²=340x(0.1+0.0008x)122.4+0.9792x...