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函数y=(sinxcosx^2)/(1+sinx)的值域是
人气:204 ℃ 时间:2020-05-21 23:07:49
解答
y=(sinxcosx^2)/(1+sinx)
=sinx(1-(sinx)^2)/(1+sinx)
=sinx(1-six)
=sinx-(sinx)^2
=-(sinx-(1/2))^2+1/4
-(3/2)^2+1/4
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