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(2cos^75度-1)/(sin75度cos75度)
人气:460 ℃ 时间:2020-06-07 03:43:39
解答
题目是(2(cos^75度)^2-1)/(sin75度cos75度)吧(2(cos^75度)^2-1)/(sin75度cos75度)=(cos150)/[(sin150)/2)]=2/tan150=-2/tan30=-2/(sqrt(3)/3)=-2*sqrt(3)用到:2sinxcosx==sin(2x)cos(2x)=2(cosx)^2-1...
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