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数学
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已知等差数列{an},且a2+a3+a10+a11=48,则a5+a8=
人气:135 ℃ 时间:2020-04-08 04:24:04
解答
a2+a3+a10+a11
=(a2+a11)+(a3+a10)
=(a5+a8)+(a5+a8)
=2(a5+a8)
=48
所以a5+a8=24
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