z=a+biz+1/z=a+bi+(a-bi)/(a^2+b^2)所以b-b/(a^2+b^2)=0b=0,或a^2+b^2=1|z-2|=2(a-2)^2+b^2=4a^2+b^2-4a=0若b=0则a=0,或a=4若a^2+b^2=1则a=0.25b=sqrt(15)/4或b=-sqrt(15)/4z的解集为z=0z=4z=0.25+0.25*sqrt(15)iz=0...