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limx趋向0 (e^x+x)^1/x
人气:457 ℃ 时间:2020-05-27 20:44:52
解答
L=lim(x->0) (e^x+x)^(1/x)
lnL =lim(x->0) ln(e^x+x) /x (0/0)
= lim(x->0)(e^x+1)/(e^x+x)
=2
L= e^2
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