函数的值域y=√[log1/2(3+2x-x^2)]≥0,log1/2(3+2x-x^2)≥0,∵对数底小于1,∴0＜3+2x-x^2≤1,解得：-1＜x≤1-√3或1+√3≤x＜3,为函数的定义域.