9×
4 |
4+1 |
1 |
5 |
=
36 |
5 |
1 |
10 |
=
36 |
50 |
大汽车相遇后通过的时间:
9×
4 |
4+1 |
50 |
3 |
=9×
4 |
5 |
3 |
50 |
=
21.6 |
50 |
36 |
50 |
21.6 |
50 |
所以用小车的倒车时间加上小汽车最后通过的时间就是两车都通过这段狭路最少用的时间:
36 |
50 |
=
36 |
50 |
9 |
50 |
=
45 |
50 |
=
9 |
10 |
答:那么两车都通过这段狭路最少用
9 |
10 |
1 |
5 |
4 |
4+1 |
1 |
5 |
36 |
5 |
1 |
10 |
36 |
50 |
4 |
4+1 |
50 |
3 |
4 |
5 |
3 |
50 |
21.6 |
50 |
36 |
50 |
21.6 |
50 |
36 |
50 |
36 |
50 |
9 |
50 |
45 |
50 |
9 |
10 |
9 |
10 |