1、[3(2x+3)+2(2x-5)][3(2x+3)-2(2x-5)]=0(10x-1)(2x+19)=0x=1/10 x=-19/22、(6x²-7x)²-2(6x²-7x) -3=0(6x²-7x-3)(6x²-7x+1)=0(3x+2)(x-3)(6x-1)(x-1)=0x=-2/3 x=3 x=1/6 x=1