极坐标方程ρ=4cosθ化为直角坐标方程是( )
A. (x-2)2+y2=4
B. x2+y2=4
C. x2+(y-2)2=4
D. (x-1)2+(y-1)2=4
人气:421 ℃ 时间:2019-10-26 11:31:25
解答
将原极坐标方程ρ=4cosθ,化为:
ρ2=4ρcosθ,
化成直角坐标方程为:x2+y2-4x=0,
即y2+(x-2)2=4.
故选A.
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