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求二重积分,被积函数是e^(-y^2/2),0
人气:268 ℃ 时间:2020-05-26 23:48:54
解答
∫∫e^(-y^2/2)dv=∫[0,1]e^(-y^2/2)dy∫[y^2,1]dx=∫[0,1](1-y^2)*e^(-y^2/2)dy
=∫[0,1]e^(-y^2/2)dy-∫[0,1]y^2*e^(-y^2/2)dy
前一项进行分部积分
=y*e^(-y^2/2) |[0,1]+∫[0,1]y^2*e^(-y^2/2)dy-∫[0,1]y^2*e^(-y^2/2)dy
=e^(-1/2)
[ , ]表示[下限,上限]
可能运算时出错,方法应该是对的,仅供参考.
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