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若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程,则m除n等于
人气:277 ℃ 时间:2019-10-08 07:28:34
解答
若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程
3m+5n=1
4m-2n=1
解得m=7/26,n=-71/35
m除n=n/m=(-71/35)/(7/26)=-1846/245是3x^3m+5n+9不是3x^3m+5n是9y^4m-2n+3不是9y^4m-2n若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程3m+5n+9=14m-2n+3=1解得m=-1,n=-1m除n=n/m=(-1)/(-1)=1
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