R1和R2两个电阻,且R1>R2,串联后接在电压为U的电路中 电流为I,并联后,接在电压为U的电路中干路电流为16/3I
那么R1:R2是
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串联时：U=i*(R1+R2)
并联时：U=(16/3)i*[(R1*R2)/(R1+R2)]
两式相除：
(R1+R2)=(16/3)*[(R1*R2)/(R1+R2)]
(R1+R2)²=(16/3)*(R1*R2)
3(R1+R2)²=16(R1*R2)
3R1²+6R1*R2+3R2²=16R1*R2
3R1²-10R1*R2+3R2²=0
(R1-3R2)*(3R1-R2)=0
R1/R2=3/1 或 R1/R2=1/3