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对z=y/(y^2+x^2)^(1/2)求全微分该怎么求
人气:409 ℃ 时间:2020-06-30 08:30:34
解答
z=y/(y^2+x^2)^(1/2)z'=-(y/2)2x/(x^2+y^2)^(3/2) = -xy/(x^2+y^2)^(3/2).z'=(x^2+y^2)^(1/2)-y^2/(x^2+y^2)^(1/2)/(x^2+y^2)=x^2/(x^2+y^2)^(3/2).dz=x(-ydx+xdy)/(x^2+y^2)^(3/2)
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