解方程1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4).1/(x-2011)(x-2012)=2012
另外,化简下面的代数式
1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4).....1/(x-2011)(x-2012)
人气:171 ℃ 时间:2020-02-04 10:22:03
解答
1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4).1/(x-2011)(x-2012)
=(1/(x-2)-1/(x-1))+(1/(x-3)-1/(x-2)).(1/(x-2012)-1/(x-2011))
=1/(x-2012)-1/(x-1)
1/(x-2012)-1/(x-1)=2012
X1=(2013+√(2033794876/503))/2
X2=(2013-√(2033794876/503))/2
推荐
猜你喜欢
- 这个禤字是怎样读的
- 括号前面是减号,脱括号要变号.那下面的要不要变号
- I don't play basketball any more,________when I was child.A.but I used to B,but I used to do .选
- 1支铅笔,2块橡皮,3个卷笔刀共花了5.3元,2支铅笔,3块橡皮,4个卷笔刀用了7.7元,3支铅笔,3块橡皮,5个
- like,guess,give,fly,tell,teach,ake,carry,play,catch,ride,study,want,watch,write,find,go,do的动词第三人称单数形式?
- 浓盐酸与稀盐酸及稀硫酸的具体区别?
- 求一句大概概括关于美国人对时间观念的英语句子.
- 因式分解c^2 - 1+ 2ab - a^2 b^2