√(x-1) - 2/3√(1-x)有意义,则x-1≥0并且1-x≥0
∴x-1=1-x=0
∴x=1
∴(2-x)/3 = (2-1)/3 = 1/3x-1=1-x=0？∵x-1≥0，1-x≥0∴x-1=1-x=0哦x=1∴(2-x)/3 = (2-1)/3 = 1/3