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(1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简
人气:198 ℃ 时间:2020-05-25 07:15:15
解答
(1-sin^4a-cos^4)/(sin^2a-sin^4a)
={1-[(sina)^2+(cosa)^2]^2+2(sina)^2*(cosa)^2}/{(sina)^2*[1-(sina)^2]}
=[2(sina)^2*(cosa)^2]/[(sina)^2*(cosa)^2]
=2
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