弧长C=9.6米,弦高H=1.2米,请问弦长L是多少?
弧半径为R,弧所对的圆心角为A.
Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*Rn
R0=10
R1=9.312
R3=9.392
R4=9.393
R5=9.393
R=9.393米
A=C/R=9.6/9.393=1.02204弧度=1.02204*180/PI=58.56度
L=2*R*SIN(A/2)=2*9.393*SIN(58.56/2)=9.188米