若实数a、b满足根号下a+1+根号下a+b=0,则代数式a的2009次方+b的2010次方的值为多少?
人气：212 ℃ 时间：2019-08-18 07:31:55
解答
√（a+1）+√（a+b）=0
则a+1=0且a+b=0,得a=-1,b=1
所以a^2009+b^2010=-1+1=0
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