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高一三角函数习题
cos36°-cos72°的值为_______.
人气:319 ℃ 时间:2020-04-09 22:25:40
解答
cos36°-cos72°
=cos(54°-18°)-cos(54°+18°)
=2sin54°sin18°=2cos36°sin18°
=2cos36°sin18°cos18°/cos18°
=cos36°sin36°/cos18°
=sin72°/(2cos18°)
=sin72°/(2sin72°)=1/2
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