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计算:x平方-1分之2x-x-1分之1
用分式化简法
人气:216 ℃ 时间:2020-03-19 23:01:41
解答
题目打的不规范
我猜应该是2x/(x^2-1)-1/(x-1)
2x/(x^2-1)-1/(x-1)
=2x/[(x+1)(x-1)]-(x+1)/[(x+1)(x-1)]
=[2x-(x+1)]/[(x+1)(x-1)]
=(x-1)/[(x+1)(x-1)]
=1/(x+1)
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