f(x)=[2sin(x+π/3)+sinx]cosx-√3sin²x=[sinx+√3cosx+sinx]cosx-√3sin²x=2sinxcosx+√3cos²x-√3sin²x=sin2x+√3cos2x=2sin(2x+π/3)1.f(x)的最小正周期=2π/2=π;2.若存在x0属于[0,5π/12],...