x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3_数学解答

x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3

人气：423 ℃　时间：2020-06-14 12:48:58

解答

x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y
=x^2-y^2+x^2-2xy+y^2-3x^2+xy
=-x^2-xy
=-(-2)^2-(-2)(1/3)
=-4+2/3
=-10/3