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(x+4)(y-1)=xy (x-2)(y+1)=xy 这个方程怎么解啊
人气:177 ℃ 时间:2019-11-19 04:38:59
解答
(x + 4)(y - 1) = xy
xy - x + 4y - 4 = xy
-x + 4y = 4 .(1)
(x - 2)(y + 1) = xy
xy + x - 2y - 2 = xy
x - 2y = 2 .(2)
(1) + (2)得
2y = 6
y = 3 .代入(2)得
x = 8
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