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求幂级数的和函数X的2n次方除以2n的阶乘
人气:331 ℃ 时间:2020-04-19 08:55:49
解答
n从0起:
ΣX^(2n)/(2n)!
=ΣX^(2n)/2^n(n)!
=Σ[X^2/2]^n/(n)!
=e^(X^2/2)不对啊,答案为,(e^(X^2)+e^(-X^2))/2看错,是不对那怎么算呢?求帮助啊~~~n从0起:2ΣX^(2n)/(2n)!=ΣX^(2n)/(2n)!+ΣX^(2n)/(2n)!=ΣX^(2n)/(2n)!+Σ(-X)^(2n)/(2n)!=ΣX^(2n)/(2n)!+Σ(X)^(2n+1)/(2n+1)!-ΣX^(2n+1)/(2n+1)!+Σ(-X)^(2n)/(2n)!=ΣX^(2n)/(2n)!+Σ(X)^(2n+1)/(2n+1)!+Σ(-X)^(2n+1)/(2n+1)!+Σ(-X)^(2n)/(2n)!=ΣX^(n)/(n)!+Σ(-X)^(n)/(n)!=e^x+e^(-x)ΣX^(2n)/(2n)!=[e^x+e^(-x)]/2
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