若数列an满足a1=1/3,且对任意正整数m,n都有am+n=am*an.设前n项和为sn,则s10-s9等于?
人气:464 ℃ 时间:2020-05-09 12:03:17
解答
令m=1
a(n+1)=a1*an
则an是以a1为公比的等比数据列
an=1/3^n
S10-S9=a10=1/3^10
推荐
- 若数列an满足a1=1/3,且对任意正整数m,n都有am+n=am*an.设前n项和为sn,则s10-s9的值是?
- 等差数列{an}中,已知a1>0,Sn为数列的前n项和,若S9>0,S10
- 数列an满足a1=1/3,an+1=an^2+an,记sn=1/(a1+1)+1/(a2+1)+.+1/(1+an),求s10的整数部分?
- 等差数列{an}中,已知a1>0,Sn为数列的前n项和,若S9>0,S10
- 在数列{an}中,a1=1,a2=2,且an+2−an=1+(−1)n(n∈N*),则S10=_.
- If your prices are competitive,we will place a large order with you.
- I perfer the pink dress to the green one.
- 写一份英语倡议书,号召大家节约用水
猜你喜欢