f(x)=2√3sinxcosx-2cos^2x+1=√3*2sinxcosx-(2cos^2x-1)=√3sin(2x)-cos(2x)=2sin(2x-π/6)∴f(x)的最小正周期=2π/2=πf(α)=2sin(2α-π/6)= -1sin(2α-π/6)= -1/22α-π/6= -π/6+kπ,k∈Z∵α∈(0,π/2)∴2α...