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对于有理数a,b,定义a⊙b=3a+2b,则计算[(x+y)⊙(x-y)]⊙3x得
人气:443 ℃ 时间:2019-10-11 12:27:11
解答
[(x+y)⊙(x-y)]⊙3x
=[3(x+y)+2(x-y)]⊙3x
=(3x+3y+2x-2y)⊙3x
=(5x+y)⊙3x
=3(5x+3y)+2×(3x)
=15x+9y+6x
=21x+9y 超简单
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