求以椭圆
+=1的焦点为焦点,且经过点P(1,
)的椭圆的标准方程.
人气:339 ℃ 时间:2020-02-03 17:12:47
解答
由已知,a
2=12,b
2=8,∴c
2=4. (2分)
设所求方程为
+=1,因为过P(1,
)
所以9n
2+40m
2=9m
2n
2. (4分)
即9(m
2-4)+40m
2=9m
2(m
2-4),解得m
2=9或
m2=(舍),
∴
+=1为所求方程. (6分)
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