解(2^m)·(8^2m)÷(4^2n-1)
=(2^m)·[(2^3)^2m]÷[(2^2)^2n-1]
=(2^m)·[(2)^6m]÷[(2)^(4n-2)]
=(2^7m)÷[(2)^(4n-2)]
=2^(7m-4n+2）