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(m^2+2m)^2-(2m+4n^2)^2因式分解
人气:307 ℃ 时间:2020-04-01 01:04:27
解答
(m^2+2m)^2-(2m+4n^2)^2
=[(m²+2m)+(2m+4n²)][(m²+2m)-(2m+4n²)]
=(m²+4m+4n²)(m²-4n²)
=(m+2n)(m-2n)(m²+4m+4n²)
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