答：2a²+6b²=32a²/3+2b²=1设a=√(3/2)cost,b=√(1/2) sinta+b=√(3/2) cost+√(1/2) sint=√2 [(√3/2)cost+(1/2)sint]=√2 sin(t+π/3)所以：a+b的最小值为-√2,最大值为√2...