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分解因式x^2-2xy+y^2+2x-2y-8
人气:403 ℃ 时间:2020-05-23 14:35:22
解答
x^2-2xy+y^2+2x-2y-8
=[x^2-2xy+y^2]+2(x-y)-8
=[x-y]^2+2[x-y]-8
=[x-y+4][x-y-2]
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