>
数学
>
根号[1-2sin(3-π)cos(3-π)]化简
人气:452 ℃ 时间:2019-11-03 21:00:47
解答
√[1-2sin(3-π)cos(3-π)]
=√[sin²(3-π)+cos²(3-π)-2sin(3-π)cos(3-π)]
=√[sin(3-π)-cos(3-π)]²
=|sin(3-π)-cos(3-π)|
=|-sin(π-3)-cos(π-3)|
因为π-3=0.141……是第一象限角,
所以原式=sin(π-3)+cos(π-3)=sin3-cos3.
也可以从头一步就用诱导公式.
化为|sin3-cos3|.
因为3是第二象限角,所以sin3>0,cos3
推荐
化简根号下1-2sin(π-3)cos(π+3)
化简1+2sin(π−2)•cos(π−2)得( ) A.sin2+cos2 B.cos2-sin2 C.sin2-cos2 D.±cos2-sin2
化简根号下1-2sin(π+4)cos(π+4)
化简1−2sin(π+3)cos(π+3)=_.
根号下(2+2sin(2π-θ)-cos^2(π+θ))可化简为
乙酸乙酯和水(NaOH作催化剂)反应化学方程式
平面匀速圆周运动中,为什么静摩擦力的方向指向圆心?
What is a process?
猜你喜欢
5克糖放入20克水中,糖占糖水的_%.
1x10的7次方 要详细的步骤,谢谢
用碳棒做电极电解NaSO4溶液阴极阳极各是什么颜色
无限个无穷小的乘积是不是无穷小?
She is (a.an.the) English teacher 选哪个.
Since they could not vote or take part in the government,they resented _____ to help pay most of the public costs.
1、Whose books are they?(翻译)2、They are my friend's books.(翻译)
若多项式x2-3x+m含有因式(x-2),则m的值是多少?
© 2024 79432.Com All Rights Reserved.
电脑版
|
手机版