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(lg5)的平方+lg2乘以lg5+(4)的log2(底数)3(对数)次幂
人气:364 ℃ 时间:2020-05-22 05:30:42
解答
(4)的log2(底数)3(对数)次幂
= [2的log2(底数)3(对数)次幂] ^2
= 3^2
= 9
(lg5)的平方+lg2乘以lg5+(4)的log2(底数)3(对数)次幂
= lg5(lg5+lg2) + 9
= lg5 + 9
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