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计算lg2的3次幂加lg5的3次幂加3倍的lg2乘以lg5
人气:340 ℃ 时间:2020-06-14 21:49:13
解答
lg2+lg5=lg2*5=lg10=1所以(lg2)^3+(lg5)^3+3*lg2*lg5=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+3*lg2*lg5=1*[(lg2)^2-lg2*lg5+(lg5)^2]+3*lg2*lg5=(lg2)^2-lg2*lg5+(lg5)^2+3*lg2*lg5=(lg2)^2+2lg2*lg5+(lg5)^2=(lg2+lg5...
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