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数学
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f(x)=2+log3X,1
人气:409 ℃ 时间:2020-06-05 14:05:52
解答
y=(2+log3x)^2+2+log3(x^2)
=(log3x)^2+4log3x+4+2log3x+2
=(log3x)^2+6log3x+6
=(3+log3x)^2-3
x∈(1,3)
log3x∈(0,1)
3+log3x∈(3,4)
(3+log3x)^2∈(9,16)
y=(3+log3x)^2-3∈(6,13)
望你满意~谢谢采纳
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