解析：由题意可知：a≠0,x+y≠0且x-y≠0若使分式x²-y²/a²x-a²y*ax+ay/（x+y）²的值等于5,那么：(x²-y²)/(a²x-a²y)*(ax+ay)/（x+y）²=5(x+y)(x-y)/[a²(x-y)]...