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求导dy/dx:y=(4+x^2)(arctan x/2)
人气:292 ℃ 时间:2019-12-25 11:29:37
解答
y'=(4+x^2)'(arctan x/2)+(4+x^2)(arctan x/2)'
=2x(arctan x/2)+(4+x²)*[1/(1+x²/4)]*1/2
=2x(arctan x/2)+(4+x²)*2/(4+x²)
=2x(arctan x/2)+2
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