解原式=[x(x-1)/(x-1)(x+1)-2/(x+1)(x-1)]÷(x-2)(x+2)/(x-1)²=[(x²-x-2)/(x-1)(x+1)]×(x-1)²/(x-2)(x+2)=(x-2)(x+1)/(x-1)(x+1)×(x-1)²/(x-2)(x+2)=(x-2)/(x-1)×(x-1)²/(x-2)(x+2)=(x-...